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calculate the mass, in grams, of 229.0 atoms of cadmium, cd. one mol of…

Question

calculate the mass, in grams, of 229.0 atoms of cadmium, cd. one mol of cd has a mass of 112.41 g.

Explanation:

Step1: Recall Avogadro's number

Avogadro's number is \( 6.022 \times 10^{23} \) atoms/mol. We need to find the number of moles of Cd from the number of atoms. The formula for moles (\( n \)) from atoms (\( N \)) is \( n=\frac{N}{N_A} \), where \( N_A \) is Avogadro's number.
So, \( n = \frac{229.0\ \text{atoms}}{6.022\times 10^{23}\ \text{atoms/mol}} \)

Step2: Calculate mass from moles

The mass (\( m \)) is given by \( m = n\times M \), where \( M \) is the molar mass (112.41 g/mol for Cd). Substitute \( n \) from Step 1 into this formula:
\( m=\frac{229.0\ \text{atoms}}{6.022\times 10^{23}\ \text{atoms/mol}}\times112.41\ \text{g/mol} \)
First, calculate \( \frac{229.0}{6.022\times 10^{23}} \approx 3.803\times 10^{-22}\ \text{mol} \)
Then, multiply by 112.41: \( 3.803\times 10^{-22}\ \text{mol}\times112.41\ \text{g/mol} \approx 4.275\times 10^{-20}\ \text{g} \)

Answer:

\( 4.275\times 10^{-20} \)