Question

calculate the number of atoms in 2.31mol titanium. a 1.39x10^24 b. 3.84x10^24 c 1.39x10^24 d. 3.84x10^24

Explanation:

Step1: Recall Avogadro's number

Avogadro's number ($N_A$) is $6.022\times 10^{23}$ atoms/mol.

Step2: Calculate the number of atoms

The number of atoms $N$ in a substance is given by $N = n\times N_A$, where $n$ is the number of moles. Here, $n = 2.31$ mol. So $N=2.31\times6.022\times 10^{23}$.
$N = 2.31\times6.022\times 10^{23}=13.81082\times 10^{23}=1.381082\times 10^{24}\approx1.39\times 10^{24}$

Answer:

C. $1.39\times 10^{24}$