Question

calculate what will be the volume of 10.0 grams of gaseous ammonia (nh₃) at stp?
a 13.2 l
b 36.9 l
c 17.1 l
d 22.7 l

Explanation:

Step 1: Calculate molar mass of \( NH_3 \)

Molar mass of \( N = 14.01 \, g/mol \), \( H = 1.008 \, g/mol \).
Molar mass of \( NH_3 = 14.01 + 3(1.008) = 17.034 \, g/mol \).

Step 2: Find moles of \( NH_3 \)

Moles \( = \frac{mass}{molar \, mass} = \frac{10.0 \, g}{17.034 \, g/mol} \approx 0.587 \, mol \).

Step 3: Use STP volume conversion

At STP, 1 mol gas = 22.4 L (approximate).
Volume \( = moles \times 22.4 \, L/mol = 0.587 \, mol \times 22.4 \, L/mol \approx 13.15 \, L \approx 13.2 \, L \).

Answer:

a. 13.2 L