Question

in a certain meeting - room, a college charges a reservation fee of $13 and an additional fee of $5 per hour. the chemistry club wants to spend at most $73 to rent the room. what are the possible numbers of hours the chemistry club could rent the meeting room? let t be the number of hours. write your answer as an inequality solved for t.

Explanation:

Step1: Set up the inequality

The total cost is the reservation fee plus the per - hour fee times the number of hours. The reservation fee is $13 and the per - hour fee is $5 per hour. Let $t$ be the number of hours. The total cost $C = 13+5t$. The club wants to spend at most $73$, so the inequality is $13 + 5t\leq73$.

Step2: Subtract 13 from both sides

To isolate the term with $t$, we subtract 13 from both sides of the inequality: $13+5t - 13\leq73 - 13$. This simplifies to $5t\leq60$.

Step3: Divide both sides by 5

Dividing both sides of the inequality $5t\leq60$ by 5 gives $\frac{5t}{5}\leq\frac{60}{5}$, which simplifies to $t\leq12$.

Answer:

$t\leq12$