Question

1. ch₄ + o₃ → co₂ + h₄o

atom reactants products
c
h
o

Explanation:

Step1: Count C atoms in reactants

In $CH_4$, there is 1 C atom. So in reactants, the number of C atoms is 1.

Step2: Count C atoms in products

In $CO_2$, there is 1 C atom. So in products, the number of C atoms is 1.

Step3: Count H atoms in reactants

In $CH_4$, there are 4 H atoms. So in reactants, the number of H atoms is 4.

Step4: Count H atoms in products

In $H_4O$ (should be $H_2O$), if we assume the correct formula is $H_2O$, for a balanced - equation consideration, we note the incorrect formula here. But if we consider the ratio, if it was correct as $H_2O$, we would need to adjust the coefficient. For now, based on the given $H_4O$, the number of H atoms is 4.

Step5: Count O atoms in reactants

In $O_3$, there are 3 O atoms. So in reactants, the number of O atoms is 3.

Step6: Count O atoms in products

In $CO_2$, there are 2 O atoms and in $H_4O$ (should be $H_2O$), there is 1 O atom. So in products, the number of O atoms is 3.

Answer:

Atom	Reactants	Products
H	4	4
O	3	3