Question

chlorine is added to a solution of sodium iodide, and a reaction occurs. the reactants are shown below. cl₂ + 2 nai →? the products of this reaction will be: a. 2icl₂ + 2na b. 2nacl + icl c. 2na + i₂ + cl₂ d. 2nacl + i₂ what is true of the ph of a solution that is an arrhenius acid? the solution will have a ph that is less than 5 the solution will have a ph that is less than 7 the solution will have a ph that is more than 5 the solution will have a ph that is more than 7

Explanation:

Step1: Analyze the first reaction

Chlorine ($Cl_2$) is more reactive than iodine. In a single - displacement reaction between $Cl_2$ and sodium iodide ($NaI$), chlorine will displace iodine. The balanced chemical equation is $Cl_2 + 2NaI=2NaCl + I_2$.

Step2: Recall the definition of Arrhenius acid

An Arrhenius acid is a substance that dissociates in water to produce hydrogen ions ($H^+$). A solution with a higher concentration of $H^+$ ions has a lower pH. By definition, acidic solutions have a pH less than 7.

Answer:

d. 2NaCl + I₂
the solution will have a pH that is less than 7