Question

choose the correct liquid on the graph by selecting the appropriate box. vapor pressure of four liquids

Explanation:

To solve this, we analyze the vapor pressure - temperature graph (though specific temp - vapor pressure relation details for each liquid's boiling point at 101.3 kPa (atmospheric pressure) are key). Boiling point is when vapor pressure = atmospheric pressure (101.3 kPa here).

Step 1: Recall Boiling Points

• Ammonia: Low boiling point (around - 33.3°C), so at lower temps, vapor pressure reaches 101.3 kPa. Its curve rises steeply, reaching 101.3 kPa at a lower temp.
• Ether: Boiling point ~ 34.6°C, vapor pressure curve (cyan) rises to 101.3 kPa at ~35°C.
• Water: Boiling point 100°C, so its vapor pressure (blue curve) reaches 101.3 kPa at 100°C.
• Ethanoic Acid: Boiling point ~ 118°C, so its vapor pressure (red curve) reaches 101.3 kPa at ~118°C.

Step 2: Match to 101.3 kPa Line

The horizontal dashed line is 101.3 kPa. We find which liquid’s curve intersects this line at its known boiling point. For example, if the question is about identifying the liquid with boiling point 100°C (water), its curve (blue) intersects 101.3 kPa at 100°C. If it’s about the lowest boiling point (ammonia), its curve (yellow) intersects 101.3 kPa at the lowest temp.

Assuming the task is to identify, say, Water (since its boiling point at 101.3 kPa is 100°C, and its curve (blue) meets 101.3 kPa at that temp), or another liquid based on the graph’s intersection.

If the question is to identify the liquid with vapor pressure reaching 101.3 kPa at 100°C, the answer is Water.

Answer:

(Example, if identifying Water) Water (the blue - colored curve on the graph, as its vapor pressure equals 101.3 kPa at 100°C, its boiling point).

(Note: The exact answer depends on the specific graph’s intersection points, but the key is using boiling point - vapor pressure relationship. If the graph shows Water’s curve intersecting 101.3 kPa at 100°C, then Water is the correct liquid.)