Question

choose the ionic compound with the greater magnitude of lattice energy. kcl cacl₂

Explanation:

Step1: Recall lattice energy factors

Lattice energy depends on ion charge and size. Higher charge and smaller size increase lattice energy.

Step2: Analyze ion charges

In \( \text{KCl} \), \( \text{K}^+ \) (charge +1) and \( \text{Cl}^- \) (charge -1). In \( \text{CaCl}_2 \), \( \text{Ca}^{2+} \) (charge +2) and \( \text{Cl}^- \) (charge -1).

Step3: Compare charges and size

\( \text{Ca}^{2+} \) has higher charge than \( \text{K}^+ \). Ionic radii: \( \text{Ca}^{2+} < \text{K}^+ \) (same period, higher charge shrinks radius). Higher charge and smaller size in \( \text{CaCl}_2 \) lead to greater lattice energy.

Answer:

\( \text{CaCl}_2 \)