QUESTION IMAGE
Question
complete the reactant or product in the following reactions. indicate type of reaction.
ca + cl₂ → ______
______ → kcl + o₂
nacl + cu(so₄) → ______
c₃h₈ + o₂ → ______
______ → nacl + br₂
______ → co₂ + h₂o
h₂ + o₂ → ______
1. $\boldsymbol{\ce{Ca + Cl2
ightarrow}}$
Step1: Identify reaction type (combination)
Calcium (Ca) and chlorine ($\ce{Cl2}$) combine.
Step2: Write product (calcium chloride)
$\ce{Ca + Cl2
ightarrow CaCl2}$ (balanced: $\ce{Ca + Cl2 = CaCl2}$)
2. $\boldsymbol{\_\_\_
ightarrow \ce{KCl + O2}}$
Step1: Identify reaction type (decomposition)
Potassium chlorate decomposes.
Step2: Write reactant (potassium chlorate)
$\ce{2KClO3 \xlongequal{\Delta} 2KCl + 3O2}$ (reactant: $\ce{KClO3}$)
3. $\boldsymbol{\ce{NaCl + Cu(SO4)
ightarrow}}$
Step1: Identify reaction type (double displacement)
Swap ions: $\ce{Na+}$ with $\ce{SO4^{2-}}$, $\ce{Cu^{2+}}$ with $\ce{Cl-}$.
Step2: Write products
$\ce{NaCl + CuSO4
ightarrow Na2SO4 + CuCl2}$ (balance: $\ce{2NaCl + CuSO4 = Na2SO4 + CuCl2}$)
4. $\boldsymbol{\ce{C3H8 + O2
ightarrow}}$
Step1: Identify reaction type (combustion)
Hydrocarbon + $\ce{O2}$ → $\ce{CO2 + H2O}$.
Step2: Write products (balance later)
$\ce{C3H8 + 5O2
ightarrow 3CO2 + 4H2O}$
5. $\boldsymbol{\_\_\_
ightarrow \ce{NaCl + Br2}}$
Step1: Identify reaction type (single displacement)
$\ce{Br-}$ displaces $\ce{Cl-}$ (reverse: $\ce{Cl2}$ displaces $\ce{Br-}$, so reactant is $\ce{NaBr + Cl2}$).
Step2: Write reactants
$\ce{2NaBr + Cl2
ightarrow 2NaCl + Br2}$
6. $\boldsymbol{\_\_\_
ightarrow \ce{CO2 + H2O}}$
Step1: Identify reaction type (combustion of hydrocarbon, e.g., $\ce{CH4}$)
Methane combustion: $\ce{CH4 + 2O2
ightarrow CO2 + 2H2O}$.
Step2: Write reactant (e.g., $\ce{CH4 + O2}$)
$\ce{CH4 + 2O2
ightarrow CO2 + 2H2O}$
7. $\boldsymbol{\ce{H2 + O2
ightarrow}}$
Step1: Identify reaction type (combination)
Hydrogen + oxygen → water.
Step2: Write product (balance)
$\ce{2H2 + O2
ightarrow 2H2O}$
Final Answers (Reactions with Balanced Equations):
- $\boldsymbol{\ce{Ca + Cl2 = CaCl2}}$ (Combination)
- $\boldsymbol{\ce{2KClO3 \xlongequal{\Delta} 2KCl + 3O2}}$ (Decomposition)
- $\boldsymbol{\ce{2NaCl + CuSO4 = Na2SO4 + CuCl2}}$ (Double Displacement)
- $\boldsymbol{\ce{C3H8 + 5O2 = 3CO2 + 4H2O}}$ (Combustion)
- $\boldsymbol{\ce{2NaBr + Cl2 = 2NaCl + Br2}}$ (Single Displacement)
- $\boldsymbol{\ce{CH4 + 2O2 = CO2 + 2H2O}}$ (Combustion, example)
- $\boldsymbol{\ce{2H2 + O2 = 2H2O}}$ (Combination)
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1. $\boldsymbol{\ce{Ca + Cl2
ightarrow}}$
Step1: Identify reaction type (combination)
Calcium (Ca) and chlorine ($\ce{Cl2}$) combine.
Step2: Write product (calcium chloride)
$\ce{Ca + Cl2
ightarrow CaCl2}$ (balanced: $\ce{Ca + Cl2 = CaCl2}$)
2. $\boldsymbol{\_\_\_
ightarrow \ce{KCl + O2}}$
Step1: Identify reaction type (decomposition)
Potassium chlorate decomposes.
Step2: Write reactant (potassium chlorate)
$\ce{2KClO3 \xlongequal{\Delta} 2KCl + 3O2}$ (reactant: $\ce{KClO3}$)
3. $\boldsymbol{\ce{NaCl + Cu(SO4)
ightarrow}}$
Step1: Identify reaction type (double displacement)
Swap ions: $\ce{Na+}$ with $\ce{SO4^{2-}}$, $\ce{Cu^{2+}}$ with $\ce{Cl-}$.
Step2: Write products
$\ce{NaCl + CuSO4
ightarrow Na2SO4 + CuCl2}$ (balance: $\ce{2NaCl + CuSO4 = Na2SO4 + CuCl2}$)
4. $\boldsymbol{\ce{C3H8 + O2
ightarrow}}$
Step1: Identify reaction type (combustion)
Hydrocarbon + $\ce{O2}$ → $\ce{CO2 + H2O}$.
Step2: Write products (balance later)
$\ce{C3H8 + 5O2
ightarrow 3CO2 + 4H2O}$
5. $\boldsymbol{\_\_\_
ightarrow \ce{NaCl + Br2}}$
Step1: Identify reaction type (single displacement)
$\ce{Br-}$ displaces $\ce{Cl-}$ (reverse: $\ce{Cl2}$ displaces $\ce{Br-}$, so reactant is $\ce{NaBr + Cl2}$).
Step2: Write reactants
$\ce{2NaBr + Cl2
ightarrow 2NaCl + Br2}$
6. $\boldsymbol{\_\_\_
ightarrow \ce{CO2 + H2O}}$
Step1: Identify reaction type (combustion of hydrocarbon, e.g., $\ce{CH4}$)
Methane combustion: $\ce{CH4 + 2O2
ightarrow CO2 + 2H2O}$.
Step2: Write reactant (e.g., $\ce{CH4 + O2}$)
$\ce{CH4 + 2O2
ightarrow CO2 + 2H2O}$
7. $\boldsymbol{\ce{H2 + O2
ightarrow}}$
Step1: Identify reaction type (combination)
Hydrogen + oxygen → water.
Step2: Write product (balance)
$\ce{2H2 + O2
ightarrow 2H2O}$
Final Answers (Reactions with Balanced Equations):
- $\boldsymbol{\ce{Ca + Cl2 = CaCl2}}$ (Combination)
- $\boldsymbol{\ce{2KClO3 \xlongequal{\Delta} 2KCl + 3O2}}$ (Decomposition)
- $\boldsymbol{\ce{2NaCl + CuSO4 = Na2SO4 + CuCl2}}$ (Double Displacement)
- $\boldsymbol{\ce{C3H8 + 5O2 = 3CO2 + 4H2O}}$ (Combustion)
- $\boldsymbol{\ce{2NaBr + Cl2 = 2NaCl + Br2}}$ (Single Displacement)
- $\boldsymbol{\ce{CH4 + 2O2 = CO2 + 2H2O}}$ (Combustion, example)
- $\boldsymbol{\ce{2H2 + O2 = 2H2O}}$ (Combination)