Question

1. complete the table below based on the isotopes provided. assume all atoms have a charge of 0.

isotope	isotope notation	atomic #	protons	electrons	neutrons
		36			48
			34		45
calcium - 40
chlorine - 37

Explanation:

Step1: Recall atomic number - proton - electron relationship

In a neutral atom, the atomic number is equal to the number of protons and the number of electrons.

Step2: Calculate neutrons

The number of neutrons is calculated by subtracting the atomic number from the mass - number (isotope mass).

For the first row:

• Since the atomic number is 15, the number of protons is 15 and the number of electrons is 15. The number of neutrons is 15. The isotope notation for an element with atomic number 15 (phosphorus) and mass - number \(15 + 15=30\) is \(_{15}^{30}P\).

For the second row:

• Atomic number is 36, so number of protons is 36 and number of electrons is 36. Number of neutrons is 48, so mass - number is \(36+48 = 84\). The element with atomic number 36 is krypton, and the isotope notation is \(_{36}^{84}Kr\).

For the third row:

• Number of electrons is 34, so number of protons is 34 (atomic number is 34). Number of neutrons is 45, so mass - number is \(34 + 45=79\). The element with atomic number 34 is selenium, and the isotope notation is \(_{34}^{79}Se\).

For calcium - 40:

• Calcium has an atomic number of 20. So number of protons is 20, number of electrons is 20, and number of neutrons is \(40 - 20=20\). The isotope notation is \(_{20}^{40}Ca\).

For chlorine - 37:

• Chlorine has an atomic number of 17. So number of protons is 17, number of electrons is 17, and number of neutrons is \(37 - 17 = 20\). The isotope notation is \(_{17}^{37}Cl\).

Isotope	Isotope Notation	Atomic #	Protons	Electrons	Neutrons
	\(_{36}^{84}Kr\)	36	36	36	48
	\(_{34}^{79}Se\)	34	34	34	45
Calcium - 40	\(_{20}^{40}Ca\)	20	20	20	20
Chlorine - 37	\(_{17}^{37}Cl\)	17	17	17	20

Answer:

Isotope	Isotope Notation	Atomic #	Protons	Electrons	Neutrons
	\(_{36}^{84}Kr\)	36	36	36	48
	\(_{34}^{79}Se\)	34	34	34	45
Calcium - 40	\(_{20}^{40}Ca\)	20	20	20	20
Chlorine - 37	\(_{17}^{37}Cl\)	17	17	17	20