Question

a) in a compound with the formula c6h14 there are atoms of carbon and atoms of hydrogen.
b) in a compound with the formula k2so4 there are ions of potassium, atom of sulfur and atoms of oxygen.
c) in a compound with the formula nh4no3 there are atoms of nitrogen, atoms of hydrogen and atoms of oxygen.
d) in a compound with the formula c3h5(oh)3 there are atoms of carbon, atoms of hydrogen and atoms of oxygen.
e) in a compound with the formula al2(so4)3 there are ions of aluminum and sulfate ions.

Explanation:

Step1: Analyze $C_6H_{14}$

The sub - script of C is 6 and of H is 14. So, there are 6 carbon atoms and 14 hydrogen atoms.

Step2: Analyze $K_2SO_4$

The sub - script of K is 2, of S is 1, and of O is 4. So, there are 2 potassium ions, 1 sulfur atom, and 4 oxygen atoms.

Step3: Analyze $NH_4NO_3$

There are 2 nitrogen atoms (1 in $NH_4^+$ and 1 in $NO_3^-$), 4 hydrogen atoms in $NH_4^+$, and 3 oxygen atoms in $NO_3^-$.

Step4: Analyze $C_3H_5(OH)_3$

There are 3 carbon atoms. The number of hydrogen atoms is $5 + 3=8$ (5 in $C_3H_5$ and 3 in $(OH)_3$). The number of oxygen atoms is 3.

Step5: Analyze $Al_2(SO_4)_3$

There are 2 aluminum ions and 3 sulfate ions.

Answer:

a) 6, 14
b) 2, 1, 4
c) 2, 4, 3
d) 3, 8, 3
e) 2, 3