Question

concept check
what is the mass of a 0.75 in³ cube of gold?
hint: density of gold = 19.34 g/cm³
express your answer to 2 sig figs. if your answer is negative, include the sign.
do not include units!
we can use either of the methods seen in the previous problem, but the in³ must first be converted to cm³.

Explanation:

Step1: Convert volume to cm³

$1\ in = 2.54\ cm$, so $1\ in^{3}=(2.54)^{3}\ cm^{3}=16.387064\ cm^{3}$. Then $V = 0.75\ in^{3}\times16.387064\ cm^{3}/in^{3}=12.290298\ cm^{3}$

Step2: Calculate mass

$m=
ho V$, where $
ho = 19.34\ g/cm^{3}$ and $V = 12.290298\ cm^{3}$. So $m=19.34\ g/cm^{3}\times12.290298\ cm^{3}=237.694363\ g$

Answer:

$237.694363\ g$