Question

consider the bohr model of an atom.
part 1 of 2
complete the following sentence.
in the bohr model, light is absorbed when an electron moves from a lower-energy orbital to a higher-energy orbital.
part 2 of 2
classify whether each transition will absorb or release light (or energy).
transition | classification
from ( n = 6 ) to ( n = 5 ) | select
from ( n = 1 ) to ( n = 4 ) | select
from ( n = 3 ) to ( n = 2 ) | select

Explanation:

Part 1 Explanation (already answered correctly as "absorbed" for electron moving from lower to higher energy orbital, since energy is needed/absorbed for the electron to jump to a higher energy level)

Part 2 Explanation:

To determine if a transition absorbs or releases light, we use the principle from the Bohr model:

• Electron moves from higher \( n \) to lower \( n \): Loses energy, so light is released (emission).
• Electron moves from lower \( n \) to higher \( n \): Gains energy, so light is absorbed (absorption).

Transition 1: From \( n = 6 \) to \( n = 5 \)

\( n = 6 \) (higher) → \( n = 5 \) (lower). Electron loses energy → release light.

Transition 2: From \( n = 1 \) to \( n = 4 \)

\( n = 1 \) (lower) → \( n = 4 \) (higher). Electron gains energy → absorb light.

Transition 3: From \( n = 3 \) to \( n = 2 \)

\( n = 3 \) (higher) → \( n = 2 \) (lower). Electron loses energy → release light.

Final Answers (Part 2 Table):

Transition	Classification
From \( n = 1 \) to \( n = 4 \)	Absorb
From \( n = 3 \) to \( n = 2 \)	Release

(For the dropdowns, select "Release" for \( n=6 \to n=5 \) and \( n=3 \to n=2 \), and "Absorb" for \( n=1 \to n=4 \).)

Answer:

Part 1 Explanation (already answered correctly as "absorbed" for electron moving from lower to higher energy orbital, since energy is needed/absorbed for the electron to jump to a higher energy level)

Part 2 Explanation:

To determine if a transition absorbs or releases light, we use the principle from the Bohr model:

• Electron moves from higher \( n \) to lower \( n \): Loses energy, so light is released (emission).
• Electron moves from lower \( n \) to higher \( n \): Gains energy, so light is absorbed (absorption).

Transition 1: From \( n = 6 \) to \( n = 5 \)

\( n = 6 \) (higher) → \( n = 5 \) (lower). Electron loses energy → release light.

Transition 2: From \( n = 1 \) to \( n = 4 \)

\( n = 1 \) (lower) → \( n = 4 \) (higher). Electron gains energy → absorb light.

Transition 3: From \( n = 3 \) to \( n = 2 \)

\( n = 3 \) (higher) → \( n = 2 \) (lower). Electron loses energy → release light.

Final Answers (Part 2 Table):

Transition	Classification
From \( n = 1 \) to \( n = 4 \)	Absorb
From \( n = 3 \) to \( n = 2 \)	Release

(For the dropdowns, select "Release" for \( n=6 \to n=5 \) and \( n=3 \to n=2 \), and "Absorb" for \( n=1 \to n=4 \).)