Question

1. consider a reaction with a theoretical yield of 100.5 g. if the percent yield for this reaction is 89.9%, what is the actual yield of product?

Explanation:

Step1: Recall percent - yield formula

Percent yield = $\frac{\text{Actual yield}}{\text{Theoretical yield}}\times100\%$.
We need to solve for actual yield. Rearranging the formula gives Actual yield = $\frac{\text{Percent yield}\times\text{Theoretical yield}}{100\%}$.

Step2: Substitute given values

Theoretical yield = $100.5$ g and percent yield = $89.9\%$.
Actual yield=$\frac{89.9\times100.5}{100}$ g.
First, calculate $89.9\times100.5 = 89.9\times(100 + 0.5)=89.9\times100+89.9\times0.5=8990 + 44.95 = 9034.95$.
Then, $\frac{9034.95}{100}=90.3495\approx90.3$ g.

Answer:

$90.3$ g