Question

considering the arrhenius equation, what is the slope of a plot of ln k versus 1/t equal to?
answer:
a k
b -k
c $e_a$
d $\frac{-e_a}{r}$
e a

Explanation:

Step1: Start with Arrhenius equation

$$k = A e^{-\frac{E_a}{RT}}$$

Step2: Take natural log of both sides

$$\ln k = \ln A - \frac{E_a}{R} \cdot \frac{1}{T}$$

Step3: Match to linear form $y=mx+b$

Here, $y=\ln k$, $x=\frac{1}{T}$, $m=-\frac{E_a}{R}$ (slope), $b=\ln A$.

Answer:

D. $\frac{-E_a}{R}$