Question

1. data for chromiums four naturally occurring isotopes is provided in the table below. calculate chromiums atomic mass.

chromium isotope date
cr - 50	4.35%	49.946
cr - 52	83.79%	51.941
cr - 53	9.50%	52.941
cr - 54	2.36%	53.939

Explanation:

Step1: Convert percentages to decimals

We need to convert the percent - abundance values to decimal form. For Cr - 50: $4.35\%=0.0435$, for Cr - 52: $83.79\% = 0.8379$, for Cr - 53: $9.50\%=0.0950$, for Cr - 54: $2.36\% = 0.0236$.

Step2: Multiply abundance by mass for each isotope

For Cr - 50: $0.0435\times49.946 = 2.172651$.
For Cr - 52: $0.8379\times51.941=43.523364$.
For Cr - 53: $0.0950\times52.941 = 5.029395$.
For Cr - 54: $0.0236\times53.939=1.27296$.

Step3: Sum up the products

$2.172651 + 43.523364+5.029395 + 1.27296=51.99837$.

Answer:

$51.998$ amu (rounded to three decimal places)