Question

determine the mass, in grams, that are in 5.32×10²² molecules of co₂?

Explanation:

Step1: Calculate the number of moles

Use Avogadro's number ($N_A = 6.022\times 10^{23}$ molecules/mol). The number of moles $n$ of $CO_2$ is given by $n=\frac{N}{N_A}$, where $N = 5.32\times 10^{22}$ molecules.
$n=\frac{5.32\times 10^{22}}{6.022\times 10^{23}}=\frac{5.32}{60.22}\approx0.0883$ mol

Step2: Calculate the molar - mass of $CO_2$

The molar - mass of $C$ is $M_C = 12.01$ g/mol and the molar - mass of $O$ is $M_O=16.00$ g/mol. For $CO_2$, $M = 12.01+2\times16.00=12.01 + 32.00=44.01$ g/mol

Step3: Calculate the mass of $CO_2$

Use the formula $m = n\times M$. Substitute $n = 0.0883$ mol and $M = 44.01$ g/mol into the formula.
$m=0.0883\times44.01\approx3.89$ g

Answer:

$3.89$ g