Question

a device in your school lab releases gas at a rate of $\frac{0.25\text{ liter}}{1\text{ second}}$, which means 0.25 of a liter of gas. the density of the gas is $\frac{4.3\text{ grams}}{1\text{ liter}}$, which means that there are 4.3 grams of the gas in one liter. find the number of seconds it will take for the device to release 154 grams of the gas. drag each tile to the correct location. the tiles can be used more than once. 154 g × $\frac{square}{square}$ × $\frac{square}{square}$ s. g l 1 4.3 0.25

Explanation:

Step1: Find volume of 154 grams of gas

Since density $
ho=\frac{m}{V}$, then $V = \frac{m}{
ho}$. Given $m = 154$ grams and $
ho=4.3$ grams per liter, so $V=\frac{154}{4.3}$ liters.

Step2: Find time to release the volume of gas

The gas - release rate is $r = 0.25$ liters per second. Time $t=\frac{V}{r}$. Substituting $V=\frac{154}{4.3}$ liters and $r = 0.25$ liters per second, we get $t=\frac{154}{4.3\times0.25}$ seconds.
The expression to fill the tiles is $154\ g\times\frac{1}{4.3\ g}\times\frac{1}{0.25\ \frac{L}{s}}$.
Calculating $t=\frac{154}{4.3\times0.25}=\frac{154}{1.075}=143.26$ seconds.

Answer:

$143.26$