QUESTION IMAGE
Question
electron configuration practice
due date:
chemistry
e. in the space below, write the full (unabbreviated) electron configurations of the following elements:
- sodium
- iron
- bromine
- barium
- magnesium
f. in the space below, write the noble gas (abbreviated) electron configurations of the following elements:
- cobalt
- chlorine
- tellurium
- radium
- rubidium
g. determine what elements are denoted by the following electron configurations:
- $1s^22s^22p^63s^23p^4$
- $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1$
- $kr 5s^24d^{10}5p^3$
- $xe 6s^2$
- $rn 7s^2$
Step1: Full config for sodium (Z=11)
$1s^22s^22p^63s^1$
Step2: Full config for iron (Z=26)
$1s^22s^22p^63s^23p^64s^23d^6$
Step3: Full config for bromine (Z=35)
$1s^22s^22p^63s^23p^64s^23d^{10}4p^5$
Step4: Full config for barium (Z=56)
$1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^2$
Step5: Full config for magnesium (Z=12)
$1s^22s^22p^63s^2$
Step6: Noble gas config for cobalt (Z=27)
$[Ar]4s^23d^7$
Step7: Noble gas config for chlorine (Z=17)
$[Ne]3s^23p^5$
Step8: Noble gas config for tellurium (Z=52)
$[Kr]5s^24d^{10}5p^4$
Step9: Noble gas config for radium (Z=88)
$[Rn]7s^2$
Step10: Noble gas config for rubidium (Z=37)
$[Kr]5s^1$
Step11: Identify element for config 11
Count electrons: $2+2+6+2+4=16$, element is Sulfur
Step12: Identify element for config 12
Count electrons: $2+2+6+2+6+2+10+6+1=37$, element is Rubidium
Step13: Identify element for config 13
Kr has 36, add $2+10+3=15$, total 51, element is Antimony
Step14: Identify element for config 14
Xe has 54, add 2, total 56, element is Barium
Step15: Identify element for config 15
Rn has 86, add 2, total 88, element is Radium
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- $1s^22s^22p^63s^1$
- $1s^22s^22p^63s^23p^64s^23d^6$
- $1s^22s^22p^63s^23p^64s^23d^{10}4p^5$
- $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^2$
- $1s^22s^22p^63s^2$
- $[Ar]4s^23d^7$
- $[Ne]3s^23p^5$
- $[Kr]5s^24d^{10}5p^4$
- $[Rn]7s^2$
- $[Kr]5s^1$
- Sulfur (S)
- Rubidium (Rb)
- Antimony (Sb)
- Barium (Ba)
- Radium (Ra)