Question

i⁻
enter your answers as integers separated by a comma.
#p⁺, #e⁻ =
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part d
ag⁺
enter your answers as integers separated by a comma.
#p⁺, #e⁻ =
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Explanation:

Step1: Find protons for I⁻

Iodine (I) has atomic number 53, so $\#p^+ = 53$

Step2: Find electrons for I⁻

Neutral I has 53 e⁻; I⁻ gains 1 e⁻, so $\#e^- = 53 + 1 = 54$

Step3: Find protons for Ag⁺

Silver (Ag) has atomic number 47, so $\#p^+ = 47$

Step4: Find electrons for Ag⁺

Neutral Ag has 47 e⁻; Ag⁺ loses 1 e⁻, so $\#e^- = 47 - 1 = 46$

Answer:

For $\text{I}^-$: 53, 54
For $\text{Ag}^+$: 47, 46