Question

in the equation 2h₂ + 1o₂ →→ 2h₂o if you change the 2h₂ to 3h₂ molecules and balance the equation, identify which statement is correct? (1 point) the result of the equation will be the same. the equation will produce three molecules of water. each oxygen molecule will combine with 2 hydrogen molecules with no leftover molecules. it is not possible to produce water without leftover molecules.

Explanation:

Step1: Write the new un - balanced equation

The original equation is $2H_2 + O_2
ightarrow2H_2O$. When we change $2H_2$ to $3H_2$, the un - balanced equation is $3H_2+O_2
ightarrow H_2O$.

Step2: Balance the new equation

In a water molecule ($H_2O$), the ratio of hydrogen to oxygen atoms is 2:1. For 3 hydrogen molecules, we need 1.5 oxygen atoms. But oxygen exists as $O_2$ molecules. To balance the equation $3H_2 + \frac{3}{2}O_2
ightarrow3H_2O$. In terms of whole - number coefficients, the balanced equation is $6H_2+3O_2
ightarrow6H_2O$. When we have 3 $H_2$ molecules reacting with 1.5 $O_2$ molecules (or in whole - number terms, 6 $H_2$ and 3 $O_2$), we will have leftover oxygen molecules if we start with an integer number of $O_2$ molecules when reacting 3 $H_2$ molecules. Each oxygen molecule combines with 2 hydrogen molecules. With 3 hydrogen molecules, we cannot combine them all with oxygen without leftovers.

Answer:

It is not possible to produce water without leftover molecules.