Question

in the equation 2h₂ + 1o₂ →→ 2h₂o. if you change the 2h₂ to 3h₂ molecules and balance the equation, identify which statement is correct? (1 point) the result of the equation will be the same. the equation will produce three molecules of water. it is not possible to produce water without leftover molecules. each oxygen molecule will combine with 2 hydrogen molecules with no leftover molecules.

Explanation:

Step1: Write the new un - balanced equation

The original equation is $2H_2 + O_2
ightarrow2H_2O$. When we change $2H_2$ to $3H_2$, the un - balanced equation is $3H_2+O_2
ightarrow H_2O$.

Step2: Balance the equation

To balance the hydrogen atoms, if we have 3 moles of $H_2$, we will get 3 moles of $H_2O$. The balanced equation becomes $3H_2+\frac{3}{2}O_2
ightarrow3H_2O$. But in terms of whole - number coefficients, we multiply through by 2 to get $6H_2 + 3O_2
ightarrow6H_2O$. When we start with $3H_2$, we need $1.5$ molecules of $O_2$ to react completely. Since we can't have a fraction of a molecule in the real - world sense of individual molecules, it is not possible to produce water without leftover molecules.

Answer:

It is not possible to produce water without leftover molecules.