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Question
example 2
element x has two naturally - occurring isotopes. the isotope with a mass of 10 amu (¹⁰x) has a relative abundance of 80 percent. the isotope with a mass of 11 amu (¹¹x) has a relative abundance of 20 percent. what is the atomic mass and identity of element x?
| isotope | % abundance | mass (amu) | mass contribution |
|---|---|---|---|
| x | |||
| total | total: |
try these yourself
- bromine has two naturally - occurring isotopes, bromine - 79 and bromine - 81. the relative abundances of the isotopes are shown below:
| isotopes | percent abundance |
|---|---|
| bromine - 81 | |
| total percentage= |
a. what is the percentage abundance of bromine - 81? write your answer in the table above (hint: percentage abundance must be equal to 100%)
b. determine the relative atomic mass of bromine.
| isotope | % abundance | mass (amu) | mass contribution |
|---|---|---|---|
| bromine - 81 | x | ||
| total | total: |
- the percentage abundances of silicon are shown below. use the data to determine relative atomic mass of silicon.
Step1: Find bromine - 81 percentage abundance
Since total percentage abundance is 100%, and bromine - 79 has 50.69% abundance. Let the abundance of bromine - 81 be $x$. Then $x=100 - 50.69$.
$x = 49.31\%$
Step2: Determine relative atomic mass of bromine
The mass of bromine - 79 is 79 amu and its abundance is 50.69% or 0.5069 in decimal form. The mass of bromine - 81 is 81 amu and its abundance is 49.31% or 0.4931 in decimal form.
The relative atomic mass $A_r$ is calculated as $A_r=(79\times0.5069)+(81\times0.4931)$.
$A_r = 79\times0.5069+81\times0.4931=39.0451 + 40.9411=79.9862\approx79.99$ amu
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a. 49.31%
b. 79.99 amu