Question

exit ticket (limiting and excess reactants, stoichiometry and % yield) - k 1 of 5 calcium carbonate reacts with hydrochloric acid according to the balanced equation: caco₃+2hcl→cacl₂+h₂o+co₂ a student calculates that the reaction should produce 12.5 g of co₂ (theoretical yield). after performing the experiment, they collect 9.20 g of co₂ (actual yield). question: what is the percent yield of carbon dioxide? (record your answer to \1\ decimal place and include the % sign in your answer.) percent yield = \\(\frac{\text{actual yield}}{\text{theoretical yield}}\\) × 100%

Explanation:

Step1: Identify given values

Actual yield = 9.20 g, Theoretical yield = 12.5 g

Step2: Apply percent yield formula

$\text{percent yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\%$
Substitute values: $\text{percent yield} = \frac{9.20}{12.5} \times 100\%$

Step3: Calculate the result

$\frac{9.20}{12.5} = 0.736$, $0.736 \times 100\% = 73.6\%$

Answer:

73.6%