Question

extra practice: complete the following table...

compound	elements present in compound & how many of each	total number of atoms in compound
alcl₃
mg₃(po₄)₂
cuso₄
nh₄cl
fe₂o₃
h₃po
na₂so₄

Explanation:

Step1: Analyze NaOH

Sodium (Na): 1 atom, Oxygen (O): 1 atom, Hydrogen (H): 1 atom. Total atoms = 1 + 1+ 1=3

Step2: Analyze AlCl₃

Aluminum (Al): 1 atom, Chlorine (Cl): 3 atoms. Total atoms = 1 + 3 = 4

Step3: Analyze Mg₃(PO₄)₂

Magnesium (Mg): 3 atoms, Phosphorus (P): 2 atoms, Oxygen (O): 8 atoms. Total atoms = 3+2 + 8=13

Step4: Analyze CuSO₄

Copper (Cu): 1 atom, Sulfur (S): 1 atom, Oxygen (O): 4 atoms. Total atoms = 1+1 + 4=6

Step5: Analyze NH₄Cl

Nitrogen (N): 1 atom, Hydrogen (H): 4 atoms, Chlorine (Cl): 1 atom. Total atoms = 1+4 + 1=6

Step6: Analyze Fe₂O₃

Iron (Fe): 2 atoms, Oxygen (O): 3 atoms. Total atoms = 2+3 = 5

Step7: Analyze H₃PO (assuming it's H₃PO₄)

Hydrogen (H): 3 atoms, Phosphorus (P): 1 atom, Oxygen (O): 4 atoms. Total atoms = 3+1 + 4=8

Step8: Analyze Na₂SO₄

Sodium (Na): 2 atoms, Sulfur (S): 1 atom, Oxygen (O): 4 atoms. Total atoms = 2+1 + 4=7

Answer:

COMPOUND	ELEMENTS PRESENT IN COMPOUND & HOW MANY OF EACH	TOTAL NUMBER OF ATOMS IN COMPOUND
AlCl₃	Al: 1, Cl: 3	4
Mg₃(PO₄)₂	Mg: 3, P: 2, O: 8	13
CuSO₄	Cu: 1, S: 1, O: 4	6
NH₄Cl	N: 1, H: 4, Cl: 1	6
Fe₂O₃	Fe: 2, O: 3	5
H₃PO₄ (assuming)	H: 3, P: 1, O: 4	8
Na₂SO₄	Na: 2, S: 1, O: 4	7