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Question
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if the gas pressure inside a 5.0 l container with 0.21 moles of oxygen is 1.0 atmosphere, the temperature of the gas is degrees celsius.
Step1: Recall ideal gas law
$PV = nRT$
Step2: Solve for temperature $T$
$T=\frac{PV}{nR}$, where $P = 1.0\ atm$, $V=5.0\ L$, $n = 0.21\ mol$, and $R = 0.0821\ L\cdot atm/(mol\cdot K)$
$T=\frac{1.0\times5.0}{0.21\times0.0821}\ K$
$T=\frac{5.0}{0.017241}\ K\approx290\ K$
Step3: Convert from Kelvin to Celsius
$T_{Celsius}=T - 273$
$T_{Celsius}=290 - 273= 17$
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