QUESTION IMAGE
Question
fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table.
| cation | anion | empirical formula | name of compound |
|---|---|---|---|
| ca²⁺ | so₃²⁻ | ||
| fe³⁺ | clo₂⁻ | ||
| pb²⁺ | bro⁻ |
Step1: Determine formula for $Ba^{2 +}$ and $NO_{2}^{-}$
The charges must balance. Two $NO_{2}^{-}$ are needed for one $Ba^{2+}$. So the empirical formula is $Ba(NO_{2})_{2}$, and the name is barium nitrite.
Step2: Determine formula for $Ca^{2+}$ and $SO_{3}^{2 -}$
The charges balance with a 1:1 ratio. The empirical formula is $CaSO_{3}$, and the name is calcium sulfite.
Step3: Determine formula for $Fe^{3+}$ and $ClO_{2}^{-}$
Three $ClO_{2}^{-}$ are needed for one $Fe^{3+}$. The empirical formula is $Fe(ClO_{2})_{3}$, and the name is iron(III) chlorite.
Step4: Determine formula for $Pb^{2+}$ and $BrO^{-}$
Two $BrO^{-}$ are needed for one $Pb^{2+}$. The empirical formula is $Pb(BrO)_{2}$, and the name is lead(II) hypobromite.
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| cation | anion | empirical formula | name of compound |
|---|---|---|---|
| $Ca^{2+}$ | $SO_{3}^{2 -}$ | $CaSO_{3}$ | calcium sulfite |
| $Fe^{3+}$ | $ClO_{2}^{-}$ | $Fe(ClO_{2})_{3}$ | iron(III) chlorite |
| $Pb^{2+}$ | $BrO^{-}$ | $Pb(BrO)_{2}$ | lead(II) hypobromite |