Question

this formula equation is unbalanced. p4(s) + 6cl2(g) → pcl3(l) which coefficient should be placed in front of pcl3 to balance this equation? 1 2 4 6

Explanation:

Step1: Count P atoms on left - hand side

On the left - hand side of the equation $P_4(s)+6Cl_2(g)\to PCl_3(l)$, the number of P atoms is 4 (from $P_4$).

Step2: Balance P atoms

To balance the P atoms on both sides of the equation, since there is 1 P atom in $PCl_3$, we need 4 moles of $PCl_3$ to have 4 P atoms on the right - hand side. So the coefficient in front of $PCl_3$ should be 4.

Answer:

C. 4