Question

give the complete electron configuration for gallium. do not use the noble gas abbreviation. ga has 1 electrons 1s² 2s² 2p⁶ 3s² 3p⁶ 2 3 4 a. 10 b. 12 c. 14 d. 16 e. 18 f. 30 g. 31 h. 28 i. 26 j. 3p⁶ k. 3p⁴ l. 3s² m. 3d¹⁰ n. 4d¹ o. 4s² p. 4p⁶ q. 5s² r. 5s⁰ s. 4d⁰ t. 4d³ u. 4p¹ v. 3p⁵

Explanation:

Step1: Determine number of electrons

Gallium (Ga) has an atomic number of 31. In a neutral atom, the number of electrons is equal to the atomic number. So Ga has 31 electrons.

Step2: Fill electron - subshells

After filling up to $3p^6$, the next sub - shells to be filled are $4s$, then $3d$, and then $4p$ according to the Aufbau principle. The $4s$ sub - shell can hold 2 electrons, the $3d$ sub - shell can hold 10 electrons and the $4p$ sub - shell starts to be filled.
The complete electron configuration after $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$ is $4s^{2}3d^{10}4p^{1}$.

Answer:

1. G. 31
2. O. $4s^{2}$
3. M. $3d^{10}$
4. U. $4p^{1}$