Question

give the noble gas abbreviated electron configuration for the only sulfur ion using the orbital (box) method. use oxidation numbers from the periodic table. s is a nonmetal and thus gains electrons to form an ion.
the s ion has 1 electrons.
the noble gas in brackets represents 2 of the total of 3 core electrons.
4 3 5 36
a. □
b. ↓
c. ↓↓
d. ↑↑
e. ↑↓
f. □□□
g. □↑□
h. ↑↓□
o. □□□□□
p. □□□□↓
q. ↓□□□↑
r. ↓□↓↑
s. ↓↓↓↑
t. ↓↑↓↓↑
u. ↓↓↑↓↓↑
v. ↑↓↑↓↓↑
cc. ↓□↑□↓
dd. ↑↓↑↑□
ee. ↑↓↑↑↑
ff. ↑↓↑↑↑↓
gg. ↓↑↓↓↓↑↑
hh. ↑↓↑↑↓↑↓
ii. ↑↓↑↑↑↓↑↓
jj. ↑↓↑↑↓↓↑↓

Explanation:

Step1: Determine sulfur ion electrons

Sulfur (S) has an atomic number of 16. It gains 2 electrons to form an ion ($S^{2 -}$), so it has 18 electrons.

Step2: Identify noble - gas core

The noble gas that precedes sulfur in the periodic table is neon (Ne) with 10 electrons. Neon represents 10 of the total 10 core electrons for the sulfur ion.

Step3: Write electron - configuration after noble - gas core

After the noble - gas core (Ne), the remaining electrons fill the 3s and 3p orbitals. The 3s orbital fills first with 2 electrons (a pair), and then the 3p orbital fills with 6 electrons. The 3s orbital is represented as [Ne] 3s$^2$ and the 3p orbital as 3p$^6$. In orbital - box notation, the 3s orbital has one box with two electrons of opposite spin (d), and the 3p orbital has three boxes with two electrons in each box (jj).

Answer:

1. 18
2. 10
3. 10
4. Ne
5. d
6. jj