Question

give the number of valence and core electrons for each. valence electrons are from the group number. core electrons are not valence electrons. it is valence electrons that are gained or lost in a chemical reaction. o has 9 valence electrons and 10 core electrons. o - 2 has 11 valence electrons and 12 core electrons. ne has 13 valence electrons and 14 core electrons. a. 0 b. 1 c. 2 d. 3 e. 4 f. 5 g. 6 h. 7 i. 8 j. 9 k. 10 l. 11 m. 12 n. 13 o. 14 p. 15 q. 16 r. 17 s. 18 t. 19 u. 20

Explanation:

Step1: Determine valence electrons of O

Oxygen (O) is in group 16 of the periodic table. Valence electrons are from the group number. So, O has 6 valence electrons.

Step2: Determine core electrons of O

O has an atomic number of 8. Core electrons = Atomic number - Valence electrons. So, core electrons = 8 - 6=2.

Step3: Determine valence electrons of O²⁻

O²⁻ is formed when O gains 2 electrons. So, valence electrons = 6 + 2=8.

Step4: Determine core electrons of O²⁻

The number of protons in O²⁻ is still 8. Core electrons remain the same as in neutral O atom relative to total electrons calculation. Core electrons = 8 - 8 = 0 (but considering the concept in terms of non - valence, for O²⁻ with 10 total electrons, core electrons = 2).

Step5: Determine valence electrons of Ne

Neon (Ne) is in group 18 of the periodic table. So, Ne has 8 valence electrons.

Step6: Determine core electrons of Ne

Ne has an atomic number of 10. Core electrons = 10 - 8 = 2.

Answer:

O has G. 6 valence electrons and C. 2 core electrons
O²⁻ has I. 8 valence electrons and C. 2 core electrons
Ne has I. 8 valence electrons and C. 2 core electrons