Question

give the systematic names of these compounds. spelling counts. cui(s): fe₂o₃(s): cof₂(s): feo(s):

Explanation:

Step1: Identify copper oxidation state in CuI

Copper can have +1 or +2 oxidation states. In CuI, iodine has a - 1 charge. For the compound to be neutral, copper has a +1 oxidation state. The name is copper(I) iodide.

Step2: Identify iron oxidation state in Fe₂O₃

Oxygen has a -2 charge. In Fe₂O₃, let the oxidation state of iron be $x$. Then $2x+3\times(- 2)=0$, solving for $x$ gives $x = +3$. The name is iron(III) oxide.

Step3: Identify cobalt oxidation state in CoF₂

Fluorine has a -1 charge. In CoF₂, let the oxidation state of cobalt be $y$. Then $y + 2\times(-1)=0$, solving for $y$ gives $y=+2$. The name is cobalt(II) fluoride.

Step4: Identify iron oxidation state in FeO

Oxygen has a -2 charge. For FeO to be neutral, iron has a +2 oxidation state. The name is iron(II) oxide.

Answer:

Copper(I) iodide
Iron(III) oxide
Cobalt(II) fluoride
Iron(II) oxide