Question

given the following atomic symbol. answer the following questions.
\\(_{26}^{55}fe^{4-}\\)
isotope name
number of protons
number of electrons
number of neutrons
ion
cation
anion
not an ion

Explanation:

Step1: Isotope name

The atomic symbol is \(\ce{_{26}^{55}Fe^{4-}}\), so the isotope name is Iron - 55 (since the mass number is 55 and the element is Iron, Fe).

Step2: Number of Protons

The atomic number (the bottom number in the atomic symbol) is equal to the number of protons. For \(\ce{Fe}\), the atomic number is 26, so the number of protons is 26.

Step3: Number of Electrons

For a neutral atom, the number of electrons equals the number of protons. But this is an ion with a charge of \(4^-\), which means it has gained 4 electrons. So the number of electrons is the number of protons plus the magnitude of the negative charge. So \(26 + 4=30\).

Step4: Number of Neutrons

The mass number (the top number in the atomic symbol) is equal to the sum of the number of protons and neutrons. So the number of neutrons is mass number minus atomic number. Mass number is 55, atomic number is 26, so \(55 - 26 = 29\).

Step5: Ion type

The ion has a negative charge (\(4^-\)), which means it has gained electrons. Anions are negatively charged ions (formed by gaining electrons), cations are positively charged (formed by losing electrons). So this is an anion.

Answer:

• Isotope name: Iron - 55
• Number of Protons: 26
• Number of Electrons: 30
• Number of Neutrons: 29
• Ion: anion (B. anion, if we consider the options as A. cation, B. anion, C. Not an ion)