Question

hcl + naoh → nacl + h₂o
25.0 ml of 1.00 m hcl is added to
75.0 ml of 1.00 m naoh. the
resulting temperature change is an
increase of 8.65 °c.
(c_{\text{sol}} = 4.20 , \text{j/g °c}) (quadquadquad) (d_{\text{sol}} = 1.02 , \text{g/ml})
what is the mass of the solution?
( \text{mass}_{\text{sol}} = ? , \text{g})

Explanation:

Step1: Calculate total volume of solution

The volume of HCl is 25.0 mL and the volume of NaOH is 75.0 mL. So the total volume \( V \) is the sum of these two volumes.
\( V = 25.0\ mL + 75.0\ mL = 100.0\ mL \)

Step2: Use density formula to find mass

The density formula is \(
ho=\frac{m}{V} \), where \(
ho \) is density, \( m \) is mass, and \( V \) is volume. Rearranging for mass gives \( m =
ho\times V \). We know the density \(
ho = 1.02\ g/mL \) and volume \( V = 100.0\ mL \).
\( m = 1.02\ g/mL\times100.0\ mL = 102\ g \)

Answer:

102