Question

how many moles of nacl are contained in each volume of aqueous nacl solution? be sure each of your answer entries has the correct number of significant figures.
note: reference the si prefixes table for additional information.
part 1 of 2
3.9 l of a 0.30 m solution
$square$ mol nacl

Explanation:

Step1: Recall molarity formula

Molarity $M = \frac{\text{moles of solute }n}{\text{volume of solution }V}$, rearranged to $n = M \times V$

Step2: Substitute given values

$M = 0.30\ \text{mol/L}$, $V = 3.9\ \text{L}$
$n = 0.30 \times 3.9$

Step3: Calculate and apply sig figs

$0.30 \times 3.9 = 1.17$, rounded to 2 significant figures (least from 0.30 and 3.9)

Answer:

1.2 mol NaCl