Question

how many particles are found in 3.00 moles of aluminum, al?
in the first box select the correct amount, in the second box select the correct unit.
options for amount: 11.85, 1.81×10²⁴, 4.98×10²⁴, 4.99×10²⁴
options for unit: atoms, formula units, molecules, moles

Explanation:

Step1: Recall Avogadro's Number

Avogadro's number is \( 6.022\times10^{23} \) particles per mole. For aluminum (a single - atom element), the number of atoms (particles) in a given number of moles is calculated by multiplying the number of moles by Avogadro's number.
The formula is \( N = n\times N_A \), where \( N \) is the number of particles, \( n \) is the number of moles, and \( N_A=6.022\times 10^{23}\space mol^{-1} \)

Step2: Substitute the values

We know that \( n = 3.00\space mol \) and \( N_A=6.022\times 10^{23}\space mol^{-1} \)
So \( N=3.00\space mol\times6.022\times 10^{23}\space mol^{-1} \)
\( N = 3.00\times6.022\times 10^{23}=1.8066\times 10^{24}\approx1.81\times 10^{24} \)
Since aluminum is an atomic substance, the particles are atoms.

Answer:

The amount is \( 1.81\times 10^{24} \) and the unit is atoms. So the first box should have \( 1.81\times 10^{24} \) and the second box should have atoms.