Question

how many valence electrons are available to create a lewis dot structure for the polyatomic ion co₃²⁻? be sure to take the charge on the polyatomic ion when considering your answer. 18 20 24 26 question 14 1 pts how many valence electrons are available to create a lewis dot structure for the polyatomic ion nh₄⁺? be sure to take the charge on the polyatomic ion when considering your answer. 10 12 4 8

Explanation:

Step1: Determine valence electrons of atoms in $CO_3^{2 -}$

Carbon has 4 valence electrons, oxygen has 6 valence electrons. There is 1 carbon and 3 oxygens. So the total from atoms is $4+(6\times3)=22$. The - 2 charge means 2 extra electrons. So total valence electrons are $22 + 2=24$.

Step2: Determine valence electrons of atoms in $NH_4^{+}$

Nitrogen has 5 valence electrons, hydrogen has 1 valence electron. There is 1 nitrogen and 4 hydrogens. So the total from atoms is $5+(1\times4)=9$. The + 1 charge means 1 less electron. So total valence electrons are $9-1 = 8$.

Answer:

Question 13: C. 24
Question 14: D. 8