Question

the hydrated compound contains the moles of anhydrous solid and water shown below. what is the coefficient for the water in the hydrated formula? 0.0370 mol fecl₃ 0.222 mol h₂o fecl₃·?h₂o hint: this is like an empirical formula. \divide by smallest\ to get the ratio.

Explanation:

Step1: Identify the moles of each component

We have 0.0370 mol of \( \text{FeCl}_3 \) and 0.222 mol of \( \text{H}_2\text{O} \).

Step2: Divide by the smallest number of moles

The smallest number of moles is 0.0370 mol (from \( \text{FeCl}_3 \)).
For \( \text{FeCl}_3 \): \( \frac{0.0370}{0.0370} = 1 \)
For \( \text{H}_2\text{O} \): \( \frac{0.222}{0.0370} = 6 \)

Answer:

The coefficient for water in the hydrated formula is 6, so the formula is \( \text{FeCl}_3 \cdot 6\text{H}_2\text{O} \).