QUESTION IMAGE
Question
an ionic compound has the formula cu₃p₂. complete the table to determine the charge of the transition metal ion in this compound. enter a negative sign before negative numbers. positive numbers do not need a positive sign.
element | charge of one ion | total charge of ion(s) in compound | number of ion(s) in compound
copper | yellow box | yellow box | yellow box
phosphorus | yellow box | yellow box | yellow box
*in one formula unit
Step1: Determine number of ions
For \( \text{Cu}_3\text{P}_2 \), number of Cu ions: 3, number of P ions: 2.
Step2: Find charge of P ion
Phosphorus (P) in ionic compounds often has a charge of \(-3\) (as phosphide ion, \( \text{P}^{3-} \)).
Step3: Calculate total charge of P ions
Total charge of P ions: \( 2 \times (-3) = -6 \).
Step4: Find charge of Cu ion
Let charge of Cu ion be \( x \). Total charge of compound is 0 (neutral). So \( 3x + (-6) = 0 \). Solving: \( 3x = 6 \) → \( x = 2 \).
Step5: Total charge of Cu ions
Total charge of Cu ions: \( 3 \times 2 = +6 \) (or 6, since positive sign is optional).
Filling the table:
- Copper:
Charge of One Ion: \( 2 \)
Total Charge of Ion(s) in Compound: \( 6 \)
Number of Ion(s) in Compound: \( 3 \)
- Phosphorus:
Charge of One Ion: \( -3 \)
Total Charge of Ion(s) in Compound: \( -6 \)
Number of Ion(s) in Compound: \( 2 \)
(If the question expects just the charge of Cu ion, the answer is \( 2 \); for the table, fill as above.)
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Step1: Determine number of ions
For \( \text{Cu}_3\text{P}_2 \), number of Cu ions: 3, number of P ions: 2.
Step2: Find charge of P ion
Phosphorus (P) in ionic compounds often has a charge of \(-3\) (as phosphide ion, \( \text{P}^{3-} \)).
Step3: Calculate total charge of P ions
Total charge of P ions: \( 2 \times (-3) = -6 \).
Step4: Find charge of Cu ion
Let charge of Cu ion be \( x \). Total charge of compound is 0 (neutral). So \( 3x + (-6) = 0 \). Solving: \( 3x = 6 \) → \( x = 2 \).
Step5: Total charge of Cu ions
Total charge of Cu ions: \( 3 \times 2 = +6 \) (or 6, since positive sign is optional).
Filling the table:
- Copper:
Charge of One Ion: \( 2 \)
Total Charge of Ion(s) in Compound: \( 6 \)
Number of Ion(s) in Compound: \( 3 \)
- Phosphorus:
Charge of One Ion: \( -3 \)
Total Charge of Ion(s) in Compound: \( -6 \)
Number of Ion(s) in Compound: \( 2 \)
(If the question expects just the charge of Cu ion, the answer is \( 2 \); for the table, fill as above.)