Question

an ionic compound has the formula pbse. complete the table to determine the charge of the transition metal ion in this compound. enter a negative sign before negative numbers. positive numbers do not need a positive sign.

element	charge of one ion	total charge of ion(s) in compound*	number of ion(s) in compound*
selenium	blank	blank	blank

*in one formula unit

what is the name of this ionic compound? dropdowns

Explanation:

Step1: Analyze Selenium ion

Selenium (Se) is in group 16, so its ion charge is -2. In PbSe, number of Se ions is 1. Total charge of Se ions: $-2 \times 1 = -2$.

Step2: Analyze Lead ion

For neutral compound, total positive charge = total negative charge. Let lead's charge be \( x \). Number of Pb ions is 1. So \( x \times 1 = +2 \), so lead's charge is +2.

Step3: Name the compound

Ionic compound: metal (lead, with charge +2) + non - metal (selenium, as selenide). Name: lead(II) selenide.

Table Completion:

• Lead:
• Charge of One Ion: \( +2 \)
• Total Charge of Ion(s) in Compound: \( +2 \) (since \( 2\times1 = 2 \))
• Number of Ion(s) in Compound: \( 1 \)
• Selenium:
• Charge of One Ion: \( -2 \)
• Total Charge of Ion(s) in Compound: \( -2 \) (since \( -2\times1=-2 \))
• Number of Ion(s) in Compound: \( 1 \)

Answer:

Table Values:

• Lead: Charge of One Ion: \( +2 \), Total Charge: \( +2 \), Number of Ions: \( 1 \)
• Selenium: Charge of One Ion: \( -2 \), Total Charge: \( -2 \), Number of Ions: \( 1 \)

Compound Name: lead(II) selenide