Question

ions to $oh^-$ ions at a ph = 6.of $h^+$ ions to $oh^-$ ions listed inguide. then divide the $h^+$concentration. record thisof your student guide.and calculated ratios of $h^+$are they the same? why ortion in table a.what is the concentration of $h^+$ ions at a ph = 6?$\boldsymbol{10^{-6}}$ $\boldsymbol{square}$ mol/lwhat is the concentration of $oh^-$ ions at a ph = 6?$\boldsymbol{10^{-8}}$ $\boldsymbol{square}$ mol/lwhat is the ratio of $h^+$ ions to $oh^-$ ions at a ph = 6?$\boldsymbol{100}$ $\boldsymbol{square}$:1

Explanation:

Step1: Calculate $[H^+]$ from pH

The formula for pH is $\text{pH} = -\log_{10}[H^+]$, so rearranged: $[H^+] = 10^{-\text{pH}}$
Substitute $\text{pH}=6$: $[H^+] = 10^{-6}$ mol/L

Step2: Calculate $[OH^-]$ from $K_w$

At 25°C, $K_w = [H^+][OH^-] = 10^{-14}$. Rearranged: $[OH^-] = \frac{10^{-14}}{[H^+]}$
Substitute $[H^+]=10^{-6}$: $[OH^-] = \frac{10^{-14}}{10^{-6}} = 10^{-8}$ mol/L

Step3: Find $[H^+]:[OH^-]$ ratio

Calculate the ratio: $\frac{[H^+]}{[OH^-]} = \frac{10^{-6}}{10^{-8}} = 100$
So the ratio is 100:1

Answer:

1. Concentration of $H^+$ ions: $\boldsymbol{10^{-6}}$ mol/L
2. Concentration of $OH^-$ ions: $\boldsymbol{10^{-8}}$ mol/L
3. Ratio of $H^+$ to $OH^-$ ions: $\boldsymbol{100:1}$