Question

ions - practice use your periodic table to complete this worksheet
standard atomic notation atomic number mass number # protons # electrons # neutrons
$_{8}^{16}o^{2 - }$
$_{11}^{23}na^{+}$
$_{17}^{35}cl$
$_{13}^{27}al^{3 + }$
14 10 14
70 34 36
15 31 18

Explanation:

Step1: Recall atomic number property

The atomic number is equal to the number of protons.

Step2: Recall electron - proton relationship for ions

For a neutral atom, number of electrons = number of protons. For a cation (positive ion), number of electrons = number of protons - charge. For an anion (negative ion), number of electrons = number of protons+ charge.

Step3: Recall mass - number formula

Number of neutrons = Mass number - Atomic number.

For \(_{8}^{16}O^{2 - }\):

• Atomic number \(Z = 8\) (from the sub - script).
• Mass number \(A=16\) (from the super - script).
• Number of protons \(= 8\) (equal to atomic number).
• Number of electrons \(=8 + 2=10\) (since it is a 2 - negative ion).
• Number of neutrons \(=16 - 8 = 8\).

For \(_{11}^{23}Na^{+}\):

• Atomic number \(Z = 11\).
• Mass number \(A = 23\).
• Number of protons \(=11\).
• Number of electrons \(=11-1 = 10\) (since it is a 1 - positive ion).
• Number of neutrons \(=23 - 11=12\).

For \(_{17}^{35}Cl\):

• Atomic number \(Z = 17\).
• Mass number \(A = 35\).
• Number of protons \(=17\).
• Number of electrons \(=17\) (neutral atom).
• Number of neutrons \(=35 - 17 = 18\).

For \(_{13}^{27}Al^{3+}\):

• Atomic number \(Z = 13\).
• Mass number \(A = 27\).
• Number of protons \(=13\).
• Number of electrons \(=13 - 3=10\) (since it is a 3 - positive ion).
• Number of neutrons \(=27 - 13 = 14\).

For the element with atomic number \(Z = 14\):

• Standard atomic notation: \(_{14}^{28}Si\) (assuming a common isotope, mass number \(A=28\) as the most abundant isotope of silicon has mass number 28).
• Number of protons \(=14\).
• Number of electrons \(=10\) (not a neutral atom here, assuming it is a 4 - positive ion \(Si^{4+}\)).
• Number of neutrons \(=28 - 14 = 14\).

For the element with mass number \(A = 70\) and 34 protons:

• Atomic number \(Z = 34\) (number of protons).
• Standard atomic notation: \(_{34}^{70}Se\) (element with atomic number 34 is selenium).
• Number of electrons \(=36\) (2 - negative ion \(Se^{2 - }\)).
• Number of neutrons \(=70 - 34 = 36\).

For the element with atomic number \(Z = 15\) and 18 neutrons:

• Mass number \(A=15 + 18=33\).
• Standard atomic notation: \(_{15}^{33}P\) (element with atomic number 15 is phosphorus).
• Number of protons \(=15\).
• Number of electrons \(=15\) (assuming neutral atom).

Answer:

Standard Atomic Notation	Atomic Number	Mass Number	# protons	# electrons	# neutrons
\(_{11}^{23}Na^{+}\)	11	23	11	10	12
\(_{17}^{35}Cl\)	17	35	17	17	18
\(_{13}^{27}Al^{3+}\)	13	27	13	10	14
\(_{14}^{28}Si^{4+}\)	14	28	14	10	14
\(_{34}^{70}Se^{2 - }\)	34	70	34	36	36
\(_{15}^{33}P\)	15	33	15	15	18