Question

isotope notation puzzle
protons\tneutrons\telectrons\tatomic number\tmass number\tanion, cation, or neither\tnet charge\tisotope notation
20\t20\t18\t\t\t\t\t
9\t10\t10\t\t\t\t\t
3\t4\t2\t\t\t\t\t
29\t33\t27\t\t\t\t\t
8\t8\t10\t\t\t\t\t
92\t146\t92\t\t\t\t\t
12\t14\t10\t\t\t\t\t
\t\t\t92\t238\t\tn\t
\t\t10\t\t19\t\t-1\t
78\t120\t78\t\t\t\t\t
\t\t\t50\t119\t\t+4\t
1\t0\t0\t\t\t\t\t
\t\t\t78\t198\tneither\t\t
19\t19\t18\t\t\t\t\t
15\t15\t15\t\t\t\t\t
23\t30\t20\t\t\t\t\t
\t\t\t5\t10\t\t+3\t
\t\t\t\t\t\t\tam-243
11\t12\t11\t\t\t\t\t
1\t\t\t\t2\t\t-1\t
29\t\t29\t\t63\t\t\t
39\t\t39\t\t89\t\t\t
35\t35\t36\t\t\t\t\t
\t\t\t\t\t\t\thg-200
3\t3\t3\t\t\t\t\t
2\t2\t2\t\t\t\t\t
48\t52\t46\t\t\t\t\t
74\t\t\t\t183\tneither\t\t
7\t8\t\t\t\t\t-3\t
52\t85\t52\t\t\t\t\t
\t\t\t\t\t\t\tbe-10+2
26\t\t\t\t55\t\tn\t
\t\t\t\t\t\t\tth-232
55\t78\t54\t\t\t\t\t
\t\t\t\t\t\t\tau-198
7\t7\t10\t\t\t\t\t
27\t\t25\t\t60\t\t\t

Explanation:

To solve the Isotope Notation Puzzle, we use the following relationships:

• Atomic Number (Z) = Number of Protons (always).
• Mass Number (A) = Protons + Neutrons.
• Net Charge = Protons − Electrons (positive = cation, negative = anion, 0 = neither).
• Isotope Notation: $\boldsymbol{^A_Z \text{Symbol}^{Charge}}$ (Symbol = element with atomic number Z).

Example: First Row (Protons=20, Neutrons=20, Electrons=18)

Step 1: Atomic Number

Atomic Number = Protons = $20$ (Element: Calcium, Ca).

Step 2: Mass Number

Mass Number = Protons + Neutrons = $20 + 20 = 40$.

Step 3: Net Charge

Net Charge = Protons − Electrons = $20 - 18 = +2$ (Cation).

Step 4: Isotope Notation

$\ce{^{40}_{20}Ca^{+2}}$

Another Example: Row with Isotope $\boldsymbol{\text{Am-243}}$

Step 1: Atomic Number (Z) for Am

Americium (Am) has Z = $95$ (from periodic table).

Step 2: Neutrons

Mass Number (A) = $243$, so Neutrons = $A - Z = 243 - 95 = 148$.

Step 3: Electrons (Net Charge = ?)

Net Charge = Protons − Electrons. For Am-243 (no charge shown, so charge = 0):
$0 = 95 - \text{Electrons} \implies \text{Electrons} = 95$.

Row with $\boldsymbol{\text{Hg-200}}$ (Mercury)

Step 1: Atomic Number (Z) for Hg

Mercury (Hg) has Z = $80$ (periodic table).

Step 2: Neutrons

Mass Number (A) = $200$, so Neutrons = $200 - 80 = 120$.

Step 3: Electrons (Net Charge = ?)

If neutral (charge = 0), Electrons = Protons = $80$.

General Formula Summary:

• $Z = \text{Protons}$
• $A = \text{Protons} + \text{Neutrons}$
• $\text{Charge} = \text{Protons} - \text{Electrons}$
• Symbol = Element with atomic number $Z$ (from periodic table).

To complete the table, apply these steps to each row using the periodic table for element symbols. For example:

Protons	Neutrons	Electrons	Atomic Number	Mass Number	Anion/Cation/Neither	Net Charge	Isotope Notation
9	10	10	9	19	Anion	-1	$\ce{^{19}_{9}F^{-}}$
...	...	...	...	...	...	...	...

(Repeat for all rows using the same logic: identify Z from protons, calculate A, charge, and symbol.)

Answer:

To solve the Isotope Notation Puzzle, we use the following relationships:

• Atomic Number (Z) = Number of Protons (always).
• Mass Number (A) = Protons + Neutrons.
• Net Charge = Protons − Electrons (positive = cation, negative = anion, 0 = neither).
• Isotope Notation: $\boldsymbol{^A_Z \text{Symbol}^{Charge}}$ (Symbol = element with atomic number Z).

Example: First Row (Protons=20, Neutrons=20, Electrons=18)

Step 1: Atomic Number

Atomic Number = Protons = $20$ (Element: Calcium, Ca).

Step 2: Mass Number

Mass Number = Protons + Neutrons = $20 + 20 = 40$.

Step 3: Net Charge

Net Charge = Protons − Electrons = $20 - 18 = +2$ (Cation).

Step 4: Isotope Notation

$\ce{^{40}_{20}Ca^{+2}}$

Another Example: Row with Isotope $\boldsymbol{\text{Am-243}}$

Step 1: Atomic Number (Z) for Am

Americium (Am) has Z = $95$ (from periodic table).

Step 2: Neutrons

Mass Number (A) = $243$, so Neutrons = $A - Z = 243 - 95 = 148$.

Step 3: Electrons (Net Charge = ?)

Net Charge = Protons − Electrons. For Am-243 (no charge shown, so charge = 0):
$0 = 95 - \text{Electrons} \implies \text{Electrons} = 95$.

Row with $\boldsymbol{\text{Hg-200}}$ (Mercury)

Step 1: Atomic Number (Z) for Hg

Mercury (Hg) has Z = $80$ (periodic table).

Step 2: Neutrons

Mass Number (A) = $200$, so Neutrons = $200 - 80 = 120$.

Step 3: Electrons (Net Charge = ?)

If neutral (charge = 0), Electrons = Protons = $80$.

General Formula Summary:

• $Z = \text{Protons}$
• $A = \text{Protons} + \text{Neutrons}$
• $\text{Charge} = \text{Protons} - \text{Electrons}$
• Symbol = Element with atomic number $Z$ (from periodic table).

To complete the table, apply these steps to each row using the periodic table for element symbols. For example:

Protons	Neutrons	Electrons	Atomic Number	Mass Number	Anion/Cation/Neither	Net Charge	Isotope Notation
9	10	10	9	19	Anion	-1	$\ce{^{19}_{9}F^{-}}$
...	...	...	...	...	...	...	...

(Repeat for all rows using the same logic: identify Z from protons, calculate A, charge, and symbol.)