Question

1. lets try another reaction. click on \combust methane\ at the bottom of the simulation. methane is ch₄. balance this reaction by changing the coefficients. 5. complete the following table for the balanced \combust methane\ reaction by typing the number of atoms of each element in the table. i need a hint element reactants products atoms var atoms var 1 carbon 2 hydrogen 3 oxygen

Explanation:

Step1: Write un - balanced reaction

The combustion of methane ($CH_4$) in oxygen ($O_2$) produces carbon dioxide ($CO_2$) and water ($H_2O$). The un - balanced reaction is $CH_4+O_2
ightarrow CO_2 + H_2O$.

Step2: Balance carbon atoms

There is 1 carbon atom on the reactant side (in $CH_4$) and 1 carbon atom on the product side (in $CO_2$), so the carbon atoms are already balanced.

Step3: Balance hydrogen atoms

There are 4 hydrogen atoms in $CH_4$ on the reactant side. In $H_2O$ on the product side, to balance the hydrogen atoms, we need 2 moles of $H_2O$ since $2\times2 = 4$. So the reaction becomes $CH_4+O_2
ightarrow CO_2+2H_2O$.

Step4: Balance oxygen atoms

On the product side, there are 2 oxygen atoms in $CO_2$ and 2 oxygen atoms in $2H_2O$, for a total of 4 oxygen atoms. On the reactant side, we need 2 moles of $O_2$ to have 4 oxygen atoms. The balanced reaction is $CH_4 + 2O_2
ightarrow CO_2+2H_2O$.

Step5: Fill in the table

• Carbon:
• Reactants: In $CH_4$, the number of carbon atoms is 1.
• Products: In $CO_2$, the number of carbon atoms is 1.
• Hydrogen:
• Reactants: In $CH_4$, the number of hydrogen atoms is 4.
• Products: In $2H_2O$, the number of hydrogen atoms is $2\times2=4$.
• Oxygen:
• Reactants: In $2O_2$, the number of oxygen atoms is $2\times2 = 4$.
• Products: In $CO_2$ there are 2 oxygen atoms and in $2H_2O$ there are 2 oxygen atoms, total 4 oxygen atoms.

Element	Reactants atoms	Products atoms
hydrogen	4	4
oxygen	4	4

Answer:

Element	Reactants atoms	Products atoms
hydrogen	4	4
oxygen	4	4