Question

in many chemical reactions of two or more compounds, ions are present in the solution that do not participate in the reaction. these ions, known as spectator ions, can be removed from the chemical equation describing the reaction. a chemical equation that has the spectator ions removed is known as a net ionic equation. reactions between ionic compounds often result in the precipitation of an insoluble compound. spectator ions and precipitation products of a chemical reaction can be predicted by consulting an ionic substance solubility table. here is one such table: compound of rule li⁺, na⁺, k⁺, or nh₄⁺ always soluble no₃⁻ or c₂h₃o₂⁻ always soluble cl⁻, br⁻, or i⁻ insoluble with ag⁺, hg₂²⁺, or pb²⁺. soluble with any other ion. so₄²⁻ soluble with all the ions except sr²⁺, ba²⁺, ca²⁺, ag⁺, hg₂²⁺, or pb²⁺ co₃²⁻ or po₄³⁻ soluble with li⁺, na⁺, k⁺, or nh₄⁺. insoluble with any other ion. oh⁻ or s²⁻ soluble with ca²⁺, sr²⁺, ba²⁺, li⁺, na⁺, k⁺, or nh₄⁺. insoluble with any other ion. entering chemical equations when entering chemical equations, please follow the following formatting guidelines: - add phases to all chemical reactions unless asked otherwise. when adding phases, make sure not to place them as a subscript. - do not stack charges and subscripts. to add a charge to an ion with a subscript, first enter the subscript. for example, to type so₄²⁻ start by typing s0₄. then use the arrow key to arrow over before adding a superscript with the charge. if you make a formatting error, you will see a message such as check your placement of subscripts and superscripts. or there is an error in your submission. make sure you have formatted it properly. you will not lose any credit, but the answer will need to be edited and re - submitted. part a what is the net ionic equation of the reaction of mgcl₂ with naoh? express you answer as a chemical equation including phases. view available hint(s)

Explanation:

Step1: Write the balanced molecular equation

$MgCl_2(aq)+2NaOH(aq)
ightarrow Mg(OH)_2(s) + 2NaCl(aq)$

Step2: Write the complete ionic equation

$Mg^{2 +}(aq)+2Cl^{-}(aq)+2Na^{+}(aq)+2OH^{-}(aq)
ightarrow Mg(OH)_2(s)+2Na^{+}(aq)+2Cl^{-}(aq)$

Step3: Identify and remove spectator ions

Spectator ions are $Na^{+}$ and $Cl^{-}$. After removing them, we get the net - ionic equation.
$Mg^{2 +}(aq)+2OH^{-}(aq)
ightarrow Mg(OH)_2(s)$

Answer:

$Mg^{2 +}(aq)+2OH^{-}(aq)
ightarrow Mg(OH)_2(s)$