Question

9 multiple choice 1 point use the given ion charges to determine the formula for chromium(iv) oxide. 4+ 2- cr? o? cr4o2 cro cro4 cro2

Explanation:

Step1: Determine charge - balance principle

In a neutral compound, total positive charge = total negative charge.

Step2: Identify ion charges

Chromium ion ($Cr$) has a charge of $4 +$ and oxygen ion ($O$) has a charge of $2 -$.

Step3: Calculate ratio of ions

Let the number of $Cr$ atoms be $x$ and number of $O$ atoms be $y$. We need $4x-2y = 0$. Solving for $\frac{x}{y}$, we get $\frac{x}{y}=\frac{2}{4}=\frac{1}{2}$. So for 1 $Cr$ atom, we need 2 $O$ atoms, giving the formula $CrO_2$.

Answer:

D. $CrO_2$