Question

3 multiple choice 2 points shown below is one of the sex pheremones from the butterfly family. how many sp hybridized carbon atoms are present in this molecule? image of a molecule with ch₃, n, and o options: 5, 3, 1, 0

Explanation:

Step1: Recall sp hybridization

sp - hybridized carbons have a linear geometry, with two sigma bonds and two pi bonds (or two double bonds, or one triple bond). They have 2 electron - rich regions around them.

Step2: Analyze the molecule

• The molecule has a five - membered ring with a nitrogen, a benzene - like (pyrrole - like) ring, a carbonyl group (\(C = O\)) and a methyl group (\(CH_3\)).
• Let's analyze each carbon:
• The carbons in the pyrrole - like ring: These are \(sp^2\) hybridized (trigonal planar, part of a double - bond - containing ring).
• The carbon in the carbonyl group (\(C = O\)): This carbon is \(sp^2\) hybridized (trigonal planar, double bond with oxygen).
• The carbon in the methyl group (\(CH_3\)): This carbon is \(sp^3\) hybridized (tetrahedral, four single bonds).
• The carbons in the saturated five - membered ring (the non - aromatic part connected to the carbonyl): These are \(sp^3\) hybridized (tetrahedral, single bonds).

• There are no carbons with a triple bond or two double bonds (which would be required for \(sp\) hybridization). So the number of \(sp\) - hybridized carbons is 0.

Answer:

0 (corresponding to the option "0")