Question

name the following
1 mo(cn)4
2 mo3(po4)4
3 mo2(hpo4)3
4 mo(h2po4)3
a. molybdenum phosphate b. molybdenum (iv) phosphate
c. molybdenum cyanide d. molybdenum (iv) cyanide
e. molybdenum (iii) phosphate f. molybdenum (iii) hydrogen phosphate
g. molybdenum (ii) hydrogen phosphate h. molybdenum (iii) dihydrogen phosphate
i. molybdenum dihydrogen phosphate j. molybdenum tetraphosphate
k. molybdenum tetracyanide

Explanation:

1. In $Mo(CN)_4$, Mo has an oxidation - state of +4 and $CN^-$ is the cyanide ion, so it is molybdenum (IV) cyanide.
2. In $Mo_3(PO_4)_4$, the phosphate ion is $PO_4^{3 - }$. Let the oxidation - state of Mo be $x$. Using the charge - balance rule: $3x+4\times(- 3)=0$, $3x = 12$, $x = + 4$. So it is molybdenum (IV) phosphate.
3. In $Mo_2(HPO_4)_3$, the hydrogen phosphate ion is $HPO_4^{2 - }$. Let the oxidation - state of Mo be $x$. Using the charge - balance rule: $2x+3\times(-2)=0$, $2x=6$, $x = + 3$. So it is molybdenum (III) hydrogen phosphate.
4. In $Mo(H_2PO_4)_3$, the dihydrogen phosphate ion is $H_2PO_4^{-}$. Let the oxidation - state of Mo be $x$. Using the charge - balance rule: $x + 3\times(-1)=0$, $x=+3$. So it is molybdenum (III) dihydrogen phosphate.

Answer:

1. D. molybdenum (IV) cyanide
2. B. molybdenum (IV) phosphate
3. F. molybdenum (III) hydrogen phosphate
4. H. molybdenum (III) dihydrogen phosphate