name:_______________________________ per:________ date:________________
mt 6 lt 4 - transition metals & ionic compounds practice
write the correct answer in below:
1. all transition metals are cations, which means they all have _____________
charges.
2. the charge on a transition metal ion when naming ionic compounds is written as
a _____________________________.
3. mercury (ii) indicates this mercury cation has a charge of _________.
4. complete the table below:
| cation | anion | name | formula |
| ---- | ---- | ---- | ---- |
| fe²⁺ | | iron (ii) carbonate | |
| | no₃¹⁻ | | agno₃ |
| ti⁴⁺ | cl¹⁻ | | |
| | | cadmium (ii) oxide | cdo |
| | s²⁻ | | cus |
| cr³⁺ | p³⁻ | | |
| | so₄²⁻ | manganese (ii) sulfate | |
| | o²⁻ | | fe₂o₃ |
| | | | cu₃n |

Question

name:_______________________________ per:________ date:________________
mt 6 lt 4 - transition metals & ionic compounds practice
write the correct answer in below:
1. all transition metals are cations, which means they all have _____________
   charges.
2. the charge on a transition metal ion when naming ionic compounds is written as
   a _____________________________.
3. mercury (ii) indicates this mercury cation has a charge of _________.
4. complete the table below:
| cation | anion | name | formula |
| ---- | ---- | ---- | ---- |
| fe²⁺ |  | iron (ii) carbonate |  |
|  | no₃¹⁻ |  | agno₃ |
| ti⁴⁺ | cl¹⁻ |  |  |
|  |  | cadmium (ii) oxide | cdo |
|  | s²⁻ |  | cus |
| cr³⁺ | p³⁻ |  |  |
|  | so₄²⁻ | manganese (ii) sulfate |  |
|  | o²⁻ |  | fe₂o₃ |
|  |  |  | cu₃n |

Accepted Answer

### Question 1
# Brief Explanations:
Cations are ions with positive charges. Transition metals as cations have positive charges.
# Answer:
positive

### Question 2
# Brief Explanations:
When naming ionic compounds with transition metals, the charge of the transition metal ion is written as a Roman numeral (in parentheses) to indicate its oxidation state.
# Answer:
Roman numeral (in parentheses)

### Question 3
# Brief Explanations:
The Roman numeral (II) after Mercury indicates the charge of the mercury cation. Roman numeral II corresponds to a charge of +2.
# Answer:
+2

### Question 4 (Table Completion)
#### Row 1: Iron (II) carbonate
## Step1: Identify anion
Carbonate ion is $\ce{CO_3^{2-}}$.
## Step2: Determine formula
To balance charges: $\ce{Fe^{2+}}$ and $\ce{CO_3^{2-}}$: 1:1 ratio? Wait, no: charge of $\ce{Fe^{2+}}$ is +2, $\ce{CO_3^{2-}}$ is -2. So formula is $\ce{FeCO_3}$.
# Anion: $\ce{CO_3^{2-}}$, Formula: $\ce{FeCO_3}$

#### Row 2: $\ce{AgNO_3}$
## Step1: Identify cation
Cation is $\ce{Ag^+}$ (silver ion, charge +1).
## Step2: Name the compound
Silver nitrate (since anion is nitrate $\ce{NO_3^-}$).
# Cation: $\ce{Ag^+}$, Name: Silver nitrate

#### Row 3: $\ce{Ti^{4+}}$ and $\ce{Cl^-}$
## Step1: Balance charges
$\ce{Ti^{4+}}$ and $\ce{Cl^-}$: need 4 $\ce{Cl^-}$ to balance +4 charge. Formula: $\ce{TiCl_4}$.
## Step2: Name the compound
Titanium (IV) chloride.
# Name: Titanium (IV) chloride, Formula: $\ce{TiCl_4}$

#### Row 4: Cadmium (II) oxide ($\ce{CdO}$)
## Step1: Identify ions
Cation: $\ce{Cd^{2+}}$ (cadmium (II) ion), Anion: $\ce{O^{2-}}$ (oxide ion).
# Cation: $\ce{Cd^{2+}}$, Anion: $\ce{O^{2-}}$

#### Row 5: $\ce{CuS}$ (anion $\ce{S^{2-}}$)
## Step1: Identify cation
Cation: $\ce{Cu^{2+}}$ (copper (II) ion, since $\ce{S^{2-}}$ is -2, so $\ce{Cu^{2+}}$ balances it: 1:1 ratio).
## Step2: Name the compound
Copper (II) sulfide.
# Cation: $\ce{Cu^{2+}}$, Name: Copper (II) sulfide

#### Row 6: $\ce{Cr^{3+}}$ and $\ce{P^{3-}}$
## Step1: Balance charges
$\ce{Cr^{3+}}$ and $\ce{P^{3-}}$: 1:1 ratio ( +3 and -3 balance). Formula: $\ce{CrP}$.
## Step2: Name the compound
Chromium (III) phosphide.
# Name: Chromium (III) phosphide, Formula: $\ce{CrP}$

#### Row 7: Manganese (II) sulfate ($\ce{SO_4^{2-}}$)
## Step1: Identify cation
Cation: $\ce{Mn^{2+}}$ (manganese (II) ion).
## Step2: Determine formula
$\ce{Mn^{2+}}$ and $\ce{SO_4^{2-}}$: 1:1 ratio? Charge +2 and -2 balance. Formula: $\ce{MnSO_4}$.
# Cation: $\ce{Mn^{2+}}$, Formula: $\ce{MnSO_4}$

#### Row 8: $\ce{Fe_2O_3}$ (anion $\ce{O^{2-}}$)
## Step1: Identify cation
Let charge of $\ce{Fe}$ be $x$. In $\ce{Fe_2O_3}$: 2$x$ + 3*(-2) = 0 → 2$x$ = 6 → $x$ = +3. So cation: $\ce{Fe^{3+}}$ (iron (III) ion).
## Step2: Name the compound
Iron (III) oxide.
# Cation: $\ce{Fe^{3+}}$, Name: Iron (III) oxide

#### Row 9: $\ce{Cu_3N}$
## Step1: Identify ions
Anion: $\ce{N^{3-}}$ (nitride ion, charge -3). Cation: $\ce{Cu^+}$ (copper (I) ion, since 3 $\ce{Cu^+}$ (3*+1) balances 1 $\ce{N^{3-}}$ (-3)).
## Step2: Name the compound
Copper (I) nitride.
# Cation: $\ce{Cu^+}$, Anion: $\ce{N^{3-}}$, Name: Copper (I) nitride

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Question 1

Answer:

Question 2

cation	anion	name	formula
	no₃¹⁻		agno₃
ti⁴⁺	cl¹⁻
		cadmium (ii) oxide	cdo
	s²⁻		cus
cr³⁺	p³⁻
	so₄²⁻	manganese (ii) sulfate
	o²⁻		fe₂o₃
			cu₃n