Question

for nos. 9 - 17, refer to the equation below: given: __ fe + cl2 → __ fecl3 9. how many grams of cl2 are there in 1.50 mol fecl3? 10. how many moles of fe are there in 2.50 mol fecl3? 11. how many grams of cl2 are there in 7.25 mol fecl3?

Explanation:

Step1: Balance the equation

$2Fe + 3Cl_2
ightarrow2FeCl_3$

Step2: Determine mole - ratio

From equation, $n(Cl_2)=\frac{3}{2}n(FeCl_3)$

Step3: Calculate moles of $Cl_2$ for 9

$n(Cl_2)=\frac{3}{2}\times1.50 = 2.25$ mol

Step4: Calculate mass of $Cl_2$ for 9

$m(Cl_2)=n\times M=2.25\times70.906\approx159.54$ g

Step5: Determine mole - ratio for 10

From equation, $n(Fe)=n(FeCl_3)$ for 1:1 ratio in balanced equation, $n(Fe) = 2.50$ mol

Step6: Calculate moles of $Cl_2$ for 11

$n(Cl_2)=\frac{3}{2}\times7.25 = 10.875$ mol

Step7: Calculate mass of $Cl_2$ for 11

$m(Cl_2)=n\times M=10.875\times70.906\approx771.43$ g

Answer:

1. 159.54 g
2. 2.50 mol
3. 771.43 g